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Thermal and Statitiscal Physics Handout

Lecture notes for the Thermal and Statistical Physics course.
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Thermal and Statistical Physics

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Thermal and Statistical Physics

Part II Michaelmas 2020

Lecture Overheads

F. Malte Grosche
September 27, 2020

Statistical Mechanics

’Ludwig Boltzmann, who spent much of his life

studying statistical mechanics, died in 1906, by his own hand.

Paul Ehrenfest, carrying on the work, died similarly in 1933.

Now it is our turn to study statistical mechanics.

Perhaps it will be wise to approach the subject cautiously.’

####### [David Goodstein — States of Matter, 1975, Dover N.]

F. M. Grosche (Cavendish Laboratory) Thermal and statistical physics 3 / 146

These boots are made for walking

Thermodynamics
Statistical mechanics
Quantum
mechanics
Thermodynamics

A warning

The slides are often complemented by blackboard work.

It is important to take copious notes in the lectures.

And: use the textbooks!

F. M. Grosche (Cavendish Laboratory) Thermal and statistical physics 7 / 146

The laws of thermodynamics

If two systems are separately in thermal equilibrium with a third, then

they must also be in thermal equilibrium with each other.

Energy is conserved when heat is taken into account.

Heat does not flow from a colder to a hotter body. [Clausius]

or

You can’t cool an object to below the temperature of its surroundings,

and extract work in the process. [Kelvin]

Internal energy

Mechanical energy (kinetic, potential) accounts for contributions to the

overall energy, which are attributed to a few macroscopic degrees of freedom.

Internal energy takes care of contributions to the overall energy, which

cannot be attributed to a few macroscopic degrees of freedom.

We think of the internal energy as residing with internal, microscopic

degrees of freedom.

This introduces the difficulty that we can put this energy in – but we do not

have enough information about internal degrees of freedom to be able to

extract all of it again.

Once energy is sunk in microscopic motion within the system, it is difficult to

get it out again. But that is what a steam engine does, so it is not

impossible. Thermodynamics lets us calculate this.

Thermodynamic variables

Systems are characterised by thermodynamic variables.

These occur in conjugate pairs of thermodynamic force (p, f , μ 0 H, T ) and

thermodynamic displacement (V , `, M, S).

Thermodynamic (or generalised) forces are always intensive: independent of

the size of the system.

Thermodynamic (or generalised) displacements are always extensive:

proportional to the size of the system.

The product of a pair of conjugate variables contributes to a

thermodynamic potential and has dimensions of energy.

Functions of state

We can find the magnitude of the change in a function of state in going between

two equilibrium states, even if the path taken was irreversible,

by choosing any convenient reversible path between the

initial and final states and integrating along it.

T 0

∮ d Q /T ≤ 0 in general

∫A

B

dQ rev /T ≥∫A

B

dQ irrev /T

for process on right

Define dQ rev /T =dS

If no heat is exchanged, dS≥ 0

irreversible

process

dQrev

reversible

process

U is a function of state, independent of reversibility

Irreversible: Q h , Q c (< 0 ) reduced

Extracted work also reduced.

Net effect on U same as reversible

cycle.

For reversible changes only:

dW ̄ (rev) = p dV + μ dN + (other relevant work terms, e. magnetic)

dQ ̄ (rev) = T dS

But generally true for reversible and irreversible changes:

dU = T dS p dV + μ dN + (other relevant work terms)

Maximum entropy principle

In approaching equilibrium, the entropy of a closed system increases:

dS =

dU + pdV

P

i μ i dN i

T

0

Two systems in thermal contact:

dS tot > 0 =) dU 1 > 0 for T 2 > T 1 and vice versa.

Two systems with particle-exchange:

dS tot > 0 =) dN 1 > 0 for μ 2 > μ 1 and vice versa.

Availability – general form of maximum entropy principle

System and reservoir (i. large system, which does not change its temperature, p

or μ).

dS tot = dS + dS R 0

= dS +

dU R + p R dV R μ R dN R

T R

=

T R dS dU p R dV + μ R dN

T R

,

Define availability A such that dA = T R dS tot :

dA = dU T R dS + p R dV μ R dN

= (T T R )dS (p p R )dV + (μ μ R )dN  0

Reservoir properties (T R , p R , μ R ) are constant =)

A = U T R S + p R V μ R N

The availability of a system in contact with a reservoir

is minimised in equilibrium

Availability for system at constant T , V , N – Helmholtz free energy

Thermal contact with reservoir fixes T = T R , dT = 0, while V and N are fixed.

(dA) T ,V ,N = (dU T R dS + p R dV μ R dN) T ,V ,N

= d(U TS) T ,V ,N ⌘ (dF ) T ,V ,N ,

F is the Helmholtz free energy.

Example: movable barrier between two gases at same temperature T.

F = F 1 + F 2 = (U 1 T 1 S 1 ) + (U 2 T 2 S 2 )

T 1 = T 2 = T , dV 2 = dV 1 , dU = TdS pdV =)

dF = (p 1 p 2 )dV 1 = 0 ) p 1 = p 2.

Phase equilibria – Gibbs free energy

Liquid-vapour transition:

At the phase transition, liquid and vapour phases coexist.

μ ` = μ v

Phase equilibria – Clausius Clapeyron equation

Phase coexistence lines in the (p, T ) plane

dm 2
dm 1

dμ 1 = dμ 2

v 1 dp s 1 dT = v 2 dp s 2 dT

=)

dp

dT

=

s 1 s 2

v 1 v 2

=

T s

T v

L

T v

Ideal gas mixtures

Entropy of mixing:

S = Nk B

X

####### i

c i ln c i

(c i = p i /p is concentration, p i is partial pressure)

Chemical potential:

μ i (p i , T ) = μ 0 i (p, T ) + k B T ln c i

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Thermal and Statitiscal Physics Handout

Module: Thermal and Statistical Physics

5 Documents
Students shared 5 documents in this course
Was this document helpful?
Thermal and Statistical Physics
Part II Michaelmas 2020
Lecture Overheads
F. Malte Grosche
September 27, 2020