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Lecture 24 Enzyme Kinetics 2
Module: Biomolecules
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University: University of Lincoln
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Enzyme Kinetics 2
● Enzyme 2 has the same KM as enzyme 1 but higher Vmax
○ Enzyme 2 has higher v0 than enzyme 1 at any substrate concentrations
● Enzyme 2 has same Vmax as enzyme 1 but lower KM
○ Enzyme 2 has higher v0 than enzyme 1 at any substrate concentrations
● Enzyme 2 has lower Vmax than enzyme 1 and lower KM
○ At low substrate concentrations v0 of enzyme 2 may be higher than enzyme 1
and opposite at high substrate concentration
○ Enzyme 2 may have lower v0 than enzyme 1 at any substrate concentrations
● Faster depletion of substrate (or appearance of product - to have a faster
reaction) can be achieved by?
○ Increase Vmax
○ Decrease of KM
○ Increase of [E]0
● Enzyme activity v0 decrease in time:
○ At any [S]0
○ At any [E]0
● Catalytic efficiency
● Equilibrium of the enzyme and substrate
● It is about how efficient the enzyme is to catalyse the reaction
● Kcat represents well the efficiency only when [ES] is high
● At low [S] concentrations, [ES] is small, so Kcat is not helpful
● Kcat/KM (units = M-1 s-1) is a better way to measure efficiency
● It reflects the rate of formation of product (Kcat) but also reflects how often
substrate and enzyme come together (KM)
○ It is called catalytic efficiency