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Test bank for linear algebra and its applications 5th edition by lay ibsn 9780134022697

Test bank for linear algebra and its applications 5th edition by lay i...
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Computatnl Linear Alg (MAS 3114)

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MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Perform the matrix operation.

####### - 3 10 - B) A- 1 =

####### - 2 - 2 -

. Find 5A.

A) - 15 5 0 10

B)

####### - 2 - 1 -

####### 2 -

C) - 15 5 0 2

D) 2 6 5 7 Answer: A

  1. Let B = - 1 1 7 - 3. Find - 4B. A) 4 - 4 - 28 12 B) - 4 4 28 - 12 C) 4 1 7 - 3 D) - 3 - 1 5 - 5 Answer: A

  2. Let C =

6

####### -

10

. Find (1/2) C.

A) 3

####### -

10

B) 6

####### 4 - 1 -

10

C) 3

####### - 1 - 3 -

5

D) 12

  • 4 20 Answer: C
  1. Let A = 3 3 2 4

and B = 0 4 - 1 6

. Find 4A + B.

A) 12 7 7 10

B) 12 16 7 22

C) 12 16 1 10

D) 12 28 4 40 Answer: B

  1. Let C =

1

  • 3 2

and D =

  • 1 3

####### - 2 - 7 -

. Find C - 2D.

A) - 3 9 - 6

B) - 1 3 - 2

C) 3

  • 9 6

D) 3

  • 6 4 Answer: C
  1. Let A = - 1 2 and B = 1 0. Find 3A + 4B. A) 1 6 B) 2 2 C) - 3 4 D) - 1 4 Answer: A

  2. Let A =

2 - 4

  • 2 - 5 3 5

and B =

9 - 8

  • 6 - 6
  • 7 - 4

. Find A + B.

A) - 7 4 4 10 - 4

B) 11 - 12 - 8 - 11 - 4 1

C) 11 - 12 8 - 5

  • 4 - 1

D) 11 - 5

  • 8 - 11
  • 4 1 Answer: B

1

Test Bank for Linear Algebra and Its Applications 5th Edition by Lay IBSN 9780134022697

Full Download: downloadlink/product/test-bank-for-linear-algebra-and-its-applications-5th-edition-by-lay-ibsn-

Full all chapters instant download please go to Solutions Manual, Test Bank site: downloadlink

  1. Let A = - 2 3
    • 7 - 2

and B = 2 10 - 7 6

. Find A - B.

A) - 4 - 7 0 - 8

B) 0 7

  • 14 8

C) 4 - 7

  • 14 4

D) 0 - 7 0 - 8 Answer: A

  1. Let A = - 3 2 3 - 5

and B = 0 0 0 0

. Find A + B.

A) 0 0 0 0

B) - 3 2 3 - 5

C) 3 - 2

  • 3 5

D) Undefined

Answer: B

Find the matrix product AB, if it is defined.

####### - 1 - 3 - C) A- 1 =

2 2

, B = - 2 0 - 1 2

#######

#######

#######

#######

#######

#######

#######

#######

#######

#######

#######

A) 6 - 1 4 - 6

B) 2 0

  • 2 4

C) - 1 6 - 6 4

D) 2 - 6

  • 1 1 Answer: C
  1. A = 0 - 3 4 3

, B = - 2 0 - 1 1

.

A) 0 6

  • 4 3

B) - 3 3 - 5 - 11

C) 3 - 3

  • 11 3

D) - 8 - 6 4 6 Answer: C

  1. A = 3 - 2 3 0

, B = 0 - 2 4 6

.

A) 0 4 12 0

B) - 18 - 8 - 6 0

C) - 8 - 18 0 - 6

D) - 6 30 - 8 Answer: C

  1. A = - 1 3 1 6

, B = 0 - 2 6 1 - 3 2

.

A) 3 6 - 7

  • 20 0 18

B) 3 - 7 0 6 - 20 18

C) 0 - 6 18 1

  • 18 12

D) AB is undefined.

Answer: B

  1. A is 2 × 4, B is 2 × 4. A) AB is undefined, BA is undefined. B) AB is 2 × 4, BA is 4 × 2. C) AB is 4 × 2, BA is 2 × 4. D) AB is 2 × 2, BA is 4 × 4. Answer: A

Find the transpose of the matrix.

8 4

  • 4 0
  • 7 7 A) 8 - 4 - 7 4 0 7

B) 4 0 7 8 - 4 - 7

C) - 7 - 4 0 8 4

D) 4 8 0 - 4 7 - 7 Answer: A

  1. 7 4 7 4 0 - 7 0 - 7 A) 4 7 4 7
  • 7 0 - 7 0

B) 7 0 4 - 7 7 0 4 - 7

C) 0 7

  • 7 4 0 7
  • 7 4

D) 0 - 7 0 - 7 7 4 7 4

Answer: B

Decide whether or not the matrices are inverses of each other.

  1. 5 3 3 2

and 2 - 3 - 3 A) No B) Yes Answer: B

  1. 10 1
    • 1 0

and 0 1 - 1 10 A) No B) Yes Answer: A

    • 2 4 - 4

and

1 2

1 4 1 2

1 4 A) Yes B) No Answer: B

    • 5 1
    • 7 1

and

1 2 -

1 2 7 2 -

5 2 A) No B) Yes Answer: B

  1. 6 - 5
    • 3 5

and

1 3

1 3 1 5

2 5 A) No B) Yes Answer: B

  1. 9 4 4 4

and - 0 0. 0 - 0. A) Yes B) No Answer: B

  1. 9 - 2 7 - 2

and

0 0.

7 4 -

9 4 A) No B) Yes Answer: A

    • 5 - 1 6 0

and

0 1 6

  • 1 5 6 A) Yes B) No Answer: B

2 - 1 0

  • 1 1 - 2 1 0 - 1

and

1 - 1 2

  • 3 - 2 4
  • 1 1 1 A) No B) Yes Answer: A

Find the inverse of the matrix, if it exists.

  1. A = - 3 - 4 3 - 4 A)
  • 1 8

1 6

  • 18 - 16

B) - 1 6

  • 1 6 1 8 -

1 8

C) - 1 8

  • 1 8

  • 1616

D) - 1 6

1 6

  • 18 - 18

Answer: D

  1. A = 0 - 5 6 3 A) 0 1 6

1 5

1 10

B) 1 10

  • 1 6 1 5

0

C) - 1 5

0

1 10

1 6

D) 1 10

1 6

1 5

0

Answer: D

Solve the system by using the inverse of the coefficient matrix. 40) 6x 1 + 5x 2 = 13 5x1 + 3x2 = 5 A) (-2, 5) B) No solution C) (-2, - 5) D) (5, - 2) Answer: A

  1. 6x 1 + 3x 2 = 0 2x1 = - 6 A) (6, - 3) B) (-3, 6) C) No solution D) (-3, - 6) Answer: B

    • 3x 1 - 2x 2 = 2 6x1 + 4x2 = 8

A) (-2, - 2) B) - 23 + 32 x2, x2 C) No solution D) (2, 8)

Answer: C

  1. 2x 1 + 6x 2 = 2 2x1 - x2 = - 5 A) (-1, 2) B) (2, - 1) C) (-2, 1) D) (1, - 2) Answer: C

  2. 2x 1 - 6x 2 = - 6 3x1 + 2x2 = 13 A) (-3, - 2) B) (-2, - 3) C) (3, 2) D) (2, 3) Answer: C

  3. 10x 1 - 4x 2 = - 6 6x1 - x2 = 2 A) (-4, - 1) B) (1, 4) C) (4, 1) D) (-1, - 4) Answer: B

  4. 2x 1 - 4x 2 = - 2 3x1 + 4x2 = - 23 A) (-2, 5) B) (2, 5) C) (-5, - 2) D) (5, 2) Answer: C

    • 5x 1 + 3x 2 = 8
    • 2x1 + 4x2 = 20 A) (2, 6) B) (-6, - 2) C) (-2, - 6) D) (6, 2) Answer: A

Find the inverse of the matrix A, if it exists.

Answer: B

Answer: B

D) A- 1 does not exist. - 5 - 48) A = -

  • 10 - - A) A- 1 = - - 1 0 - - - 1 0 B) A- 1 does not exist. C) A- 1 = - 0 1 - - - D) A- 1 = - - 0 1 - - - -
      1. A =
    •     - - 1 - 1 - A) A- 1 =
          - - 2 - 1 -
          - - 2 - 2 -
                            - - B) A- 1 =
                                     - 4 - 1 -
                            - -
                                  - C) A- 1 does not exist. D) A- 1 =
                               -
                               -
                                           -
                               -
                               -
                                        -
                                        -
                                              -
                                              -
      1. A =
    •        - A) A- 1 =
                   -
                      -
                      -
             -
                   -
                      -
                      -
             -
             -
                   -
                   -
                      -
                      -
                            - - 3 10 - B) A- 1 =
                                     - 2 -
                            - -
          - - 1 - 3 - C) A- 1 =
          - - 1 - 3 -
          - - 2 - 7 -

Determine whether the matrix is invertible.

  1. 2 9 1 14 A) No B) Yes Answer: B

9 5 - 9 4 2 - 4

  • 3 0 3 A) No B) Yes Answer: A

Identify the indicated submatrix.

  1. A =

0 1 - 4 - 5 4 - 1 0 7 2 5 - 7 0

. Find A12.

A) 4 B) - 5 7

C) 1 D) 2 5 - 7

Answer: B

  1. A =

2 6 1

  • 2 0 - 1 0 3 - 6 3 6 3

. Find A21.

A)

1

  • 1
  • 6

B) - 2 C) 6 D) 3

Answer: D

Find the matrix product AB for the partitioned matrices.

  1. A =

4 0 1 2 - 1 - 3 5 3 7

, B =

  • 2 0 8 5 1 6 2 2 4 - 1 0 3

A) - 4 - 1 32 23

  • 17 - 3 14 - 1 21 11 46 52

B) - 8 0 32 20 - 5 - 6 14 8 - 7 18 46 C)

  • 4 - 1 0 3
  • 12 - 3 0 - 9 28 - 7 0 21

D) - 4 - 1 32 23

  • 17 - 3 14 - 1 21 11 46 52 Answer: D
  1. A = 0 I I F

, B = W X Y Z

A) Y Z W + YF X + ZF

B) X W + XF Z Y + ZF

C) 0 Z FY FZ

D) Y Z W + FY X + FZ Answer: D

Solve the equation Ax = b by using the LU factorization given for A.

  1. A =

3 - 1 2

  • 6 4 - 5 9 5 6

, b =

6

  • 3 2

A =

1 0 0

  • 2 1 0 3 4 1

3 - 1 2 0 2 - 1 0 0 4

A) x =

22

  • 7 15

B) x =

25

  • 58 51

C) x =

49

  • 38 32

D) x =

10

  • 2
  • 13 Answer: D
  1. A =

1 2 4 3

  • 1 - 3 - 1 - 4 2 1 19 3 1 5 - 9 7

, b =

2 0 4 3

A =

1 0 0 0

  • 1 1 0 0 2 3 1 0 1 - 3 - 2 1

1 2 4 3 0 - 1 3 - 1 0 0 2 0 0 0 0 1

A) x =

27 9 8

  • 3

B) x =

27

  • 18 89
  • 13

C) x =

2

  • 2 8
  • 3

D) x =

41

  • 6
  • 3
  • 5 Answer: D

Find an LU factorization of the matrix A.

  1. A = 4 - 1
    • 24 9

A) A = 1 0 - 6 1

4 - 1 0 3

B) A = 1 0 4 1

  • 6 - 1 0 3 C) A = 1 0
  • 6 1

4 1 0 - 3

D) A = 1 0 6 1

  • 4 - 1 0 - 3 Answer: A

Find the 3 × 3 matrix that produces the described transformation, using homogeneous coordinates. 68) (x, y) → (x + 7, y + 4) A) 1 0 4 0 1 7 0 0 1

B) 1 0 7 0 1 4 0 0 0

C) 1 0 7 0 1 4 0 0 1

D) 7 0 0 0 4 0 0 0 1 Answer: C

  1. Reflect through the x-axis A) 1 0 0 0 - 1 0 0 0 1

B) - 1 0 0 0 1 0 0 0 1

C) - 1 0 0 0 - 1 0 0 0 1

D) 1 0 0 0 1 0 0 0 1 Answer: A

Find the 3 × 3 matrix that produces the described composite 2D transformation, using homogeneous coordinates. 70) Rotate points through 45° and then scale the x-coordinate by 0 and the y-coordinate by 0. A) 0 2 0 2 0

  • 0 2 0 2 0 0 0 1

B) 0 - 0 2 0 0 2 0 0 0 0 1 C) 0 - 0 0 0 0 0 0 0 1

D) 0 2 - 0 2 0 0 2 0 2 0 0 0 1 Answer: D

  1. Translate by (8, 6), and then reflect through the line y = x. A) 0 1 8 1 0 6 0 0 1

B) 0 1 6 1 0 8 0 0 1

C) 0 6 1 8 0 0 0 0 1

D) - 1 0 - 8 0 - 1 - 6 0 0 1 Answer: B

Find the 4 × 4 matrix that produces the described transformation, using homogeneous coordinates. 72) Translation by the vector (4, - 6, - 3) A) 4 0 0 0 0 - 6 0 0 0 0 - 3 0 0 0 0 1

B) 1 0 0 4 0 1 0 - 6 0 0 1 - 3 0 0 0 1

C) 0 0 0 4 0 0 0 - 6 0 0 0 - 3 0 0 0 1

D) 1 0 0 - 4 0 1 0 6 0 0 1 3 0 0 0 1 Answer: B

  1. Rotation about the y-axis through an angle of 60° A) 0 0 3 /2 0 0 1 0 0
  • 3 /2 0 0 0 0 0 0 1

B) 1 0 0 0 0 0 3 /2 0 0 - 3 /2 0 0 0 0 0 1 C) 0 3 /2 0 0

  • 3 /2 0 0 0 0 0 1 0 0 0 0 1

D) 3 /2 0 0 0 0 1 0 0

  • 0 0 3 /2 0 0 0 0 1 Answer: A

Determine whether b is in the column space of A.

  1. A =

1 2 - 3 1 4 - 6

  • 3 - 2 5

, b =

1

  • 2
  • 3 A) No B) Yes Answer: B
  1. A =
  • 1 0 2 5 8 - 10
  • 3 - 3

, b =

  • 4 3 4 A) Yes B) No Answer: B

Find a basis for the null space of the matrix.

  1. A =

1 0 - 7 - 4 0 1 5 - 2 0 0 0 0

A) 7

  • 5 1 0

,

4 2 0 1

B) - 7 5 1 0

,

  • 4
  • 2 0 1

C) 1 0 0

,

0 1 0

D) 1 0

  • 7
  • 4

,

0 1 5

  • 2 Answer: A
  1. A =

1 0 - 4 0 - 4 0 1 2 0 2 0 0 0 1 1 0 0 0 0 0

A) 4

  • 2 1 0 0

,

4

  • 2 0
  • 1 1

B) 1 0

  • 4 0
  • 4

,

0 1 2 0 2

C) 1 0 0 0

,

0 1 0 0

,

0 0 1 0

D) - 4 2 1 0 0

,

  • 4 2 0
  • 1 1 Answer: A

Determine the rank of the matrix.

1 - 2 2 - 3 2 - 4 7 - 2

  • 3 6 - 6 9

A) 4 B) 1 C) 3 D) 2 Answer: D

1 0 - 4 0 4 0 1 - 3 0 4 0 0 0 1 1 0 0 0 0 0

A) 3 B) 4 C) 5 D) 2 Answer: A

16

Test Bank for Linear Algebra and Its Applications 5th Edition by Lay IBSN 9780134022697

Full Download: downloadlink/product/test-bank-for-linear-algebra-and-its-applications-5th-edition-by-lay-ibsn-

Full all chapters instant download please go to Solutions Manual, Test Bank site: downloadlink

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Test bank for linear algebra and its applications 5th edition by lay ibsn 9780134022697

Course: Computatnl Linear Alg (MAS 3114)

7 Documents
Students shared 7 documents in this course
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MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Perform the matrix operation.
1)
Let A =
-3 1
0 2 . Find 5A.
A)
-15 5
0 10
B)
-15 1
0 2
C)
-15 5
0 2
D)
2 6
5 7
Answer:
A
2)
Let B =
-1 1 7 -3
. Find -4B.
A)
4 -4 -28 12
B)
-4 4 28 -12
C)
4 1 7 -3
D)
-3 -1 5 -5
Answer:
A
3)
Let C =
6
-2
10
. Find (1/2) C.
A)
3
-2
10
B)
6
-1
10
C)
3
-1
5
D)
12
-4
20
Answer:
C
4)
Let A =
3 3
2 4 and B =
0 4
-1 6 . Find 4A + B.
A)
12 7
7 10
B)
12 16
7 22
C)
12 16
1 10
D)
12 28
4 40
Answer:
B
5)
Let C =
1
-3
2
and D =
-1
3
-2
. Find C - 2D.
A)
-3
9
-6
B)
-1
3
-2
C)
3
-9
6
D)
3
-6
4
Answer:
C
6)
Let A =
-1 2
and B =
1 0
. Find 3A + 4B.
A)
1 6
B)
2 2
C)
-3 4
D)
-1 4
Answer:
A
7)
Let A =
2-4
-2-5
3 5
and B =
9-8
-6-6
-7-4
. Find A + B.
A)
-7 4
4 4
10 -4
B)
11 -12
-8-11
-4 1
C)
11 -12
8-5
-4-1
D)
11 -5
-8-11
-4 1
Answer:
B
1
Test Bank for Linear Algebra and Its Applications 5th Edition by Lay IBSN 9780134022697
Full Download: http://downloadlink.org/product/test-bank-for-linear-algebra-and-its-applications-5th-edition-by-lay-ibsn-9780134022697/
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