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Derivative Practice

diffferential practice
Course

Mathematics 1 (AMATH1S)

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Practice Problems on Derivative Computing (with Solutions)

This problem set is generated by Di. All of the problems came from past exams of Math 221. For

derivative computing – unlike many of other math concepts – more lectures do not help much, and

nothing compares to practicing on one’s own! The idea of this problem set is to get enough practice,

till the point that it becomes hard to make any mistake. :)

  1. y=

√ 3

x 2 sinx

  1. y=tanx x 3 +

  2. y=

(

x 4 + sinxcosx

) 3

  1. y=x

3 − 2 x x+

  1. y=

(√

x 2 −1 + 1

) 10

  1. y= cos

(

x 2

)

tan

(√

x+ 1

)

  1. y= cos (cos (cos (3x)))

  2. y=

1+x 2 −x

  1. y=x 2 (

x+ 2)

10(x) = 2

x 2 + 1 + sin

( 4 π 5

)

11(x) = 2 sinx−x 3

12=x 3 + 2 x 13 −√ 32 x

13= sin (5x) cos (3x)

14=

(

cos

(

x 2

)

  • cos 2 x

) 4

15= 12 +xcosx+x 5

16=

(

x 2 +x− 1

)

sinxcos 2 x

17= cos

(

x 2 +xx+

)

18=x

2 − 2 x 4 +

19=x 2

√ 3

tanx

20=

(√

x 2 + 1 +x

) 5

21=

1 −cosx(tanx)

3

22=

sin(x 3 ) sin(x 2 )

23=x 3 + sin (x) cos 2 (x)

24=x(10x+ 6)

2011

25=

(sinx)

3 + 1

26= tan

(

x 4 + 3x 2 + 1

)

27=

sin(3x) 1+x 4

28= (5−2 cosx)

3 2

29= (

x+ 3)

80

30=

1 xsin

− 4 (x)−

x 3 cos

3 (x)

31=

tan(2x) (x+5) 4

32= tan

(

cos(x) x

)

33= sin

(

√x x 2 +

)

34= sin 5

(

3 x 4 − 7 x

)

The following problems involveexand lnx, which we haven’t seen in our lecture so far, but we

will learn them later. We could practice them later when the materialis covered. To do them, you

need to know:

(e

x )

′ =e

x ,(lnx)

′ =

1

x

,

darctanx

dx

=

1

1 +x 2

.

  1. f(x) =xln

(

e 2 x+ 2

)

  1. y= arctan

(

e 4 x+ 3x

)

  1. y= ln

(

x+

x 2 − 1

)

  1. y= 3 ln (xsinx)

  2. y=e−tan(x+1)

  3. y= sin

(

lnx+ 3x 2

)

  1. y= e

x 2 x+

  1. y=

lnx+ 1

  1. y=e

√ x 2 +

10= ln

(

2 (1+x 2 ) x 4

)

11= lne 2 x

12= arctan (x−1) +

sin (lnx)

13=x 2 e 3 x

2 − 5 x

14= ln (4x+ 6)e 5 x

19=x 2 (tanx)

1 3

y′= 2x(tanx)

1 3 +x 21 3 (tanx)

− 23 sec 2 x

20′= 5

(√

x 2 + 1 +x

) 4 (

1 2

(

x 2 + 1

)− 1

22 x+ 1

)

21= (1−cosx)

1 2 (tanx) 3

y′=

1 2 (1−cosx)

− 12 sinx(tanx)

3 + (1−cosx)

1 2 3 (tanx) 2 sec 2 x

22′=

cos(x 3 ) 3 x 2 sin(x 2 )−cos(x 2 ) 2 xsin(x 3 ) [sin(x 2 )] 2

23′= 3x 2 + cos 3 x+ sinx·2 cosx(−sinx)

24′= (10x+ 6)

2011 +x2011 (10x+ 6)

2010 10

25=

(

(sinx)

3 + 1

) 1

2

y′= 12

(

(sinx)

3 + 1

)− 1

2 3 (sinx)

2 cosx

26′= sec 2

(

x 4 + 3x 2 + 1

) (

4 x 3 + 6x

)

27′=

cos(3x)3(1+x 4 )− 4 x 3 sin(3x) (1+x 4 ) 2

28′= 32 (5−2 cosx)

1 2 (2 sinx)

29′= 80 (

x+ 3)

79

(

5 2 x

− 12

)

  1. For the 1st term, you can also do quotient rule. Here I rewrite it as a product, so that I can kill people. :)

y=x− 1 sin− 4 (x)−x 3 cos 3 x

y′=−x− 2 sin− 4 (x) +x− 1 (−4) sin− 5 (x) cos (x)− 13 cos 3 x−x 3 3 cos 2 x(−sinx)

31′=

sec 2 (2x)2(x+5) 4 −4(x+5) 3 tan(2x) (x+5) 8

32′= sec 2

(cosx x

)−sinx·x−cosx x 2

33′= cos

(

√x x 2 +

)√

x 2 +1− 12 (x 2 +1)

− 12 2 x 2 x 2 +

34′= 5 sin 4

(

3 x 4 − 7 x

) (

12 x 3 − 7

)

Well, I guess no one works till the last problem together with me... I admit computing derivatives

could be pretty boring and exhausted. But if you finished all of these problems, I believe derivative

computing will become part of your nature, and you can do them quickly andaccurately. Now it’s

time to say: I came, I calculated, I conquered. :)

Some irrelevant aside by Di:Typing solutions is also very exhausted! Half way through typing,

I started to question myself why do I want to tortune myself on doing this extra amount of work.

lol Well... But if this is helpful to anyone in any sense, then it worths the time and effort. Also if

there’s any typo, please kindly let me know!

  1. f′(x) = ln

(

e 2 x+ 2

)

+e 2 xx+2e 2 x 2

  1. y′= 1 1+(e 4 x+3x) 2

(

4 e 4 x+ 3

)

  1. y′=

1+ 12 (x 2 − 1 )

− 12 2 x x+

√ x 2 − 1

  1. y′=xsin 3 x(sinx+xcosx)

  2. y′=e−tan(x+1)

(

−sec 2 (x+ 1)

)

  1. y′= cos

(

lnx+ 3x 2

) ( 1

x+ 6x

)

  1. y′=

ex

2 2 x(x+3)−ex

2

(x+3) 2

  1. y′= 12 (lnx+ 1)

− 121 x

  1. y′=e

√ x 2 +1 1 2

(

x 2 + 1

)− 1

22 x

10= ln 2 + ln

(

1 +x 2

)

−4 lnx

Here we used the properties of logarithm that we’ll learn later:

ln (ab) = lna+ lnb,ln

(

a

b

)

= lna−lnb.

y′=

2 x 1+x 2 −

4 x

11= lne 2 x= 2x

y′= 2

12′= 1 1+(x−1) 2

  • 12 (sin (lnx))

− 12 cos (lnx) 1 x

13′= 2xe 3 x

2 − 5 x +x 2 e 3 x

2 − 5 x (6x−5)

14′= 4 x 4 +6e 5 x+ ln (4x+ 6)e 5 x 5

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Derivative Practice

Course: Mathematics 1 (AMATH1S)

71 Documents
Students shared 71 documents in this course
Was this document helpful?
Practice Problems on Derivative Computing (with Solutions)
This problem set is generated by Di. All of the problems came from past exams of Math 221. For
derivative computing unlike many of other math concepts more lectures do not help much, and
nothing compares to practicing on one’s own! The idea of this problem set is to get enough practice,
till the point that it becomes hard to make any mistake. :)
1. y=3
x2sin x
2. y=tan x
x3+2
3. y=x4+ sin xcos x3
4. y=x32x
x+3
5. y=x21 + 110
6. y= cos x2tan x+ 1
7. y= cos (cos (cos (3x)))
8. y=q1+x
2x
9. y=x2(x+ 2)
10. f(x) = 2x2+ 1 + sin 4π
5
11. h(x) = sin x
2x3
12. y=x3+1
2x32
3
x
13. y= sin (5x) cos (3x)
14. y=cos x2+ cos2x4
15. y= 12 + xcos x+x5
16. y=x2+x1sin xcos2x
17. y= cos x2+x
x+1
18. y=x22
x4+1
19. y=x23
tan x
20. y=x2+ 1 + x5
21. y=1cos x(tan x)3
22. y=sin(x3)
sin(x2)
23. y=x3+ sin (x) cos2(x)
1