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Mathematics Class 9 Real Numbers Topic 1 and 2

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Engineering Mathematics I (2K6EN101)

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a Quick ,. Rt1bon wntl..-71 Review TOPIC-1 Rational tn Sumber the form : A p. number q, Numbers where ,. 1' r and ,s calle q ar d e a r co-p ational rime integers num be~ , .. 1f an JI d can q -t 1,e 0,

denoted For C\ amplc Symbolrcallv, by (l 2'. 1 4' 4 5' Q 2 3 "" clc. {1?. q' are q all O raand tiona. p, q I numberE ,J s.

roPlC -• • • ~,. ~.) r na 1 ;rr.,. r.. ,. Decimal Expansion of Real Numbers : The dee imal r expansion of real roPIC -P liz 5 ciu:J,. .,r r r' V• _ .,• ;,.-,:-:: 1, Cases in Rational Number: numbe r It. the dcall>d eau--ed a. mal rational number. ex to pansion of a real numbens either repre, ent a number on the number.. 1 emunating me. or non-t be p emunating (q -t 0) can recurribe expreng, ssed than as a dea..,, the real;_ e. Case di\i ding : (i) 1 : .!. 2 'When Remainder becomes Zero - p by = 0 q, when the remainder becomes zero, then the ecun Every · rational al num d. so r al q' 1 is called is a terminating a terminatidng eamal. decimal. On (ii) dividing 100 52 = 0. 52 1 by 2, we get value 0 i., remamder equ lo zero, 2 52.. tJ d. I On Case 2 by terminating recurring q, dividing when remainder never becomes zero : When remainder never becomes zero - A rational 52 by 100, or we get repeating decimal. value 0 i., and It remainder equal is denoted by the bar set of digits repeats periodicall y thnumber to zero, so -over expressed in 100 it. JS a term the an form ma the deamal ng of p. ea q or ma. is d1\ cafld 1510! e. On dividing (ii) : (1). 1 = - 3 0 = 0 1 by 3, ...... .. we get 3 again and again = = 0. 0 - 3 i., remainder never becomes zero, 50 113 is a repeating decim , There are infinitely many rational numbers between ,. On dividing 3 by Every integer is a rational number. 11 11, we get 27 again and again i., remainder neve any two ·. gnen r comes zero. be rational. numbersSo,. J 111 is a repeatin g de , (ili)x If (i) (ii) x and x x - x + y y y y is is are is a a a rational number any rational number rational number two rational numbers, then : (iv) x + y is a rational number, (y # OJ.

Q. l. L, ---"F.: ,Ris -J2 a rational number or not? Q. So, 2. Write ,~ 177 413 is a rational number. the simplest form of a rational number 1 R Sol. Q. 177 - U3 3. Find = 59x3 59x7 the decimal expansion of =~- 7 1000. 1 Sol. places 1000 58 = to 0 the left) (Decimal [Board Term point I, 2015, is shifted Set 20UIYN] three 1 R Q. 4. Calculate fraction ?_ 8 the. decimal [CBSE Marking which Scheme, represents 2015] the R Sol. Q. 7 5. = Write a real deci mal expansion. J. number which has terminating 1 [Q] Sol. QfG)nsert - 125 J1 = 0. three rational numbers between - ~ and 1 --. 2 3 [Board Term I, 2016, Set JQ22L5C]

Sol. and -- 1 3 2 3 - - ---- 12 4 12 8 1 So three rational --12' 5 numbers [CBSE -- 12 6 and--. Marking are 12 7 Scheme, 2016} [Ql Sol. Q@ Find two rational numbers between [Board Term 4 = - 4 5 x 5 I, 2016, and 5 4 Set and = - JQ22L5C] 5 5 5. x 5 i., The 1\umbers are 21 5 4 and = - 20 5 22 5 and 5= - 25 lQl Q. 8. Express where p the and rational q are [CBSE integers number Marking an4 0 q:;:. Scheme, in 0. the form 20161 p q , Sol. Let, lOx lOx - x x = = = 0 9 .... (9 ..... ) -.... (0 [Board .999 ....... ) Term I, 20141 ½ lUJ Q. 9. Calculate 9x x=l the =9 value of 2 in the form of P ½ q where p and q are integers and q :;:. O.

REAL NUMBERS Sol. ·nvo r.1tion num1'1'f'ii

t,i,1wc-rn n I 2221 (md O 1414414 At' ll ilnd 0 " 14 and l!\l le.) ,, imd ll\l 50 (CBSU .\1.. Schrmc, 201h) Q. t,. ln~11 thin• rahon.

3 numbn~ bctWl'cn. ,ind 5 IBfl Tetm I, 2012, Set

&O] Sol. lCM 0f Sand i i~ 35

3 7 21 3 - = -x-i::-s 7 3S ¼ and

5 2$ 5 = -x-=-¼ i 3:i 7 5 11. 23 24 25 ~,, -"-

¼ ~-<-<-<- 35 35 35 35 35 The required three ratw

nal numbers are , 35 35 and 35

½ (CBSE Marking Scheme,

2012] - p U Q. 7. Express 0 in the form of - , where

p and q are -

q integers and q:;. 0.

[Board Term I, 2013] Sol Let,

x = 0 X = 0.................

.. .. (i) multiplying 10 on both the sides, we get, 10 X = 6. .... (ii) 1 From (ii)-(i), we get 9x =

6 6 2 X = -=-9 3 A Q. 8. Represent 0.

in the form of E.., where

p and q q are integers and q :;. 0. [Board

Sol. Term I, 2012, Set 38] I 000 c .)

[ 5 217 237 X = m [CBSE Marking Scheme, 2012I

Alternative Method : Let r - 0.

= 0 ...... > lOOOx :.-237. ........

1/z > ]()(){)x X "'(237 7237

. ... ) - (Q .... )

1/z 999x = 237

1/z 237 x=-

¼ 999 fA! Q. 9. Express the decimal number 2.

in the form of E., where p and q are

integers and q:;. 0. q [Board Term I, 2012, Set 41] Sol. Let X

= 2 = 2. ........ lOx = 22. ........

½ lO00x = 2218.... . 1/z 1000x-10x = (2218.

..... J-(22 .... J 990x = 2196 ¼ x = 2196 2x3x3x122 122 1/z 990 2x3x3x55 55 [CBSE Marking Scheme, 2012] [BJ Q. is not a rational number as AA

and .ffs -. are not rational. State whether

it is true or false. Justify your answer [Board

Term I, 2012, Set-39] Sol. False Justification: AA=

fM7" = @"_ = .ffs V75 vzs s which is a rational number. (CBSE Marking Scheme, 2012]

Short Answer

Type Questions-I

I

3 marks each

-u Q. Find three rational

numbers between and

.2... 7 11 [Board Term I, 2014] Sol. Since LCM of 7 and

11 is 77, ==!.!.=~

1 771177 and 5=5=11=55 771177 Hence, three rational numbers between and .2.. are : 7

56 57 58 77'77'77 IQ] Q. 2. Find six rational numbers between 3 and

  1. [Board Term I, 2014] Sol. Let a = 3 and b = 4 Here, we find six rational

numbers, i., n = 6 b-a 4-3 1 Sod=-=-=- n+l 6+1 7 51 1 rational number= a+

d = 3 + .!_ = ½ 7 7

"""

6 l '

BSE Que~

"1A,. Oswaal_ -"

o. ~- , 2 ii 1 2"'' '••li, 11 ,,11111111 111 ,, [!" ,. ~,-:i r •

6 6 5 30 I I = x - = - "' 5 x c, 30 5 ISO 5 7 I 1 l,I ½ :11\1 r,1ti.,,1 11 111111>,,r •

4 ,li/ , , J t ; c 7 11 2.'i I

½ I'" 1,1ti1111,1l n 11111 1'i,, ,,

., ,I,/ c: l l 7 • 7 21 ,

½ ;ih lllliu11,1l 11 11 111h1•1 ' ,

:;,1 • .l I 7 • 7 1111 ' 1,1 11 ,1 11 ,1l 11111nh1•1 ,1 I

r, 27 (1d ,1 I ½ 7 7 '2 21 24 25 2/i S11, ~,, 1,1tin 11 ,,1 1111111hl

•r~ ,111• ; , ' 7' 7' 7

7 Hild ~ i

I I U Q, ,l hnd lour r, 1110

11,11 nurnbcrs between 5

and Sol.

[Board Tenn I, 2012, Set-

781 S 111 r ,• I .CM of 5 ,llld 6 is

30 I I S 5525 • :: X - :: > - ½ 6 65 3 1Js Long Answer

Type Questions R Q lJGive two rational numbers

whose : (i) difference is a ration al number, (ii) sum is a rational numbe

r, (iii) produ ct is a rational number, (iv) division is a rational numbe

r. /usli/y also. (Board

Term I, 2015, Set 2] Sol. Any example and verification of example: Let 111 4 /5, 11 = 9/2 Difforcnrr 9 _ 4 ,, 37 (Rational Number) 2 5 10 4 9 53 Sum + (Rational Number) 5 2 IO 4 9 36 (Raticmal Number) X l'rmluct I() 5 2 945 4 Diviion. + (R,1tion,1l Number) 2 5 8 l}, Q12Arr,111g1• in ch 1 ·rcndini; ordt•r lfi, ~'

'ff and '". jBuard

Term I, 2012, Set 57]

Hi•ncc, lour rational A/ numbers ~ 61 "%~ I ,1r1?: 6 26 27 28 29 ,so' IS{)' 150' ISO ½,.½~ [CBSE Marking S chelti - p e Q Express 0. 328 in the 4

fonn of - , Wh· '.. q IChire and q -t 0. [Board Ternq , Sol. Let

X = 0 28 _ O ' --32828 10x = 3, 282828 I. 1000x = 328 .282828 ... JOOOOx- 10 x = 328. 2828. • 3)-SGJ 990 x = 325 325 65 x=,,__ 990 198 [CBSE Marking Sche1t1e, 4 rnarkse~ Sol. LCM of 3, 4, 6, and

--... 12 is 12. ,,,i 'ti, "2-' 2 'm I 3 ,, 5 12 I~ vs "5' I l 712 ifj "7' 'ffl I ';/3 "31? "';/3 Descending order is 'ms, 'm, 'm, ,;13 1 i., 1/5, ifi, ifj., ;/3 [CBSE Marking Scheme,llll:

Alternative Method : Since, LCM of 3, 4, 6, 12 is 12 1 ·. V2=2l•: =2~ ='fr' ='m 13 J vs= z,·, = 2" = '½' = 'ifuf, I l I ifi = 7' ·, = 7" = 'fi' = 'ffl ';/3 " ';/3 In Descending order '~, 'ffl, 'l/16, '(3 i., 1/5, 'ff, fi., ';/3.

§l __

05waal CBSE Question B

1 ank, MATHEMATICS

I Cl~

Very Short

Answer Type

Questions

1 markeq, 1

F' Q, l. ldcnhly an

mahon,11 number ,1mong

the followin& number~

o o, orns, 0:1001300013..

[Board Term I, 2014] Sol. 0. D i, J lcmun,1lmg

number So, 1l is not

an urati(lnal number. Cl~ = 0.

15" repeating continuou

sly, '('I 11 ts not an ITTJlion l number. ODis = 0. 13151315. , 1s repeating continuously, so 11 i, not ,111 1rrahonal

number. O.'l0130(l\300013. ., non-terminating

and non- recurring deon1al. Henc

e, it is an irrational number. So, 0 i, an irrational number.

1 R Q. l. ls lhe product

of two irrational numbers

always an irrational number? Sol. No, it may be rational or irrational.

R Q. 3. Write the sum

of 2,/s and Sol. Sum of 2,/s and = 2,/s + U Q, 4 :C:alculate the irrational number

1 between 2 'li

  • Sol. Since, Js = 2 Hence, the irrational

number between 2 and

2 Js. 8- Q. 5. Simplify the number (

  • Jsj2 · Sol. (fi.+Jsj2 = (J'i.)

+(Jsj2 = 2+s+2,Jw. = 7 + 2M (Irrational Number).

Short Answer

Type Questions-I

2marks eacn

B Q. 1. Find any two

irrational numbers between

  1. and 0.

[Board Term I, 2014] Sol. Required two irrational number

are : (i). ..... .... (ti). ..... .. . S: Q. 2. Find any two

irrational numbers between

  1. and 0. [Board

Term I, 2012, Set 14] Sol. 0....

and 0 ..... [CBSE Marking

[i] Q. Scheme, 2012] 3. Find an irrational number

between and 7 when it is given that!

= 0. 7 [Board Term I, 2012 , Set 5~ Sol,

  • = 0.142.........

1 / 2 7 = 0. ..... Hence, required number

can be 0 ... [CBSE Marking Scheme

, 20121

Short Answer

Type Questions

-I I

3 marks each

JI Q. 1. Find three irrational

numbers between i and

ii. [Board Term I, 2016, Set

7AEDLQR, NCERT] Sol.

5 -- 7 = 0·714285 9 - 11 = 0·81 Hence three inrrational numbers between

and 7 ! can be: 11

0·n7'227222 ........... 0·737337333 ........... Q·74 7447444 ........... [CBSE

Marking Scheme, 20161 IAl Q. 2. Represent ./

on the number line. [Board Term Sol. ...,.,.; I -2 -1 Let

I, 20131

,ff,,, ... LU 0 1 P 02 A B AB = BC = 1 unit length

t-+ .. 3

####### ) ,.

REAL NUMSERS

[ 9

l ,in~ l'yth,~'r,1, th,--.,n·m

, ,, l' ~,•t• th

A Q lh•prc,cn l f~

5 on the number line. /5. ex·• ,- 1 i. !

) [Board Term I, 2014

l\m,tn1ct CD • I unit

kn~h r,•rr1.•ndkul,1r to

OC th,•n u,m~ l) th,1~,,r,1, th,·,,rcm ,

w,• ,l'c th,1t ()I) ,(,'/~1i::.J3 ,,, ll, ing ,.1 .:omp,1,, with centre

O ,ind r On, Jr,.1"· .m .l'1: which mh:r,.t',t~ the numl:,l'r line

.it the r-,int (l, th,m (l ''-'l'TC~~"'"d~

to .J A Q. J Kcr~nt , 5

0n thl' num~•r lim·. [Board Torm L 201 4,

BQS6IZK) Sol. \'e know th,.1t, ,/s

2 O = ,':f+l , ·2~ + 1 0 '"' - 1 -2 0 3 Dra,,· a right angll?d __

OBA., such that C'B = 2 units. :.B = 1

= 90 ° unit and LOBA ::S:ow b,· using P•,thago ras theorem ,

we have 2.. OA" = 0B 1 2 2 2 +AB= 2 +1 OA = ,M=. 1 :'ow, take O as centre ,

OA = __ as radius, draw an arc which intersects the line at point

C. Hence, the point C represents

1 .. [CBSE Marking Scheme, 2014] A Q. -.. Represent .J9

on the number line. 2016, Set 20CNJE9] [Board Term I, Sol

_D ./······ .......... ../95 •v:s • I BC E A O +--9.~ Marks the distance 9.

units from a fixed point A on a given line to obtain a point B such that 9 units from AB =

B, marks a distance of 1 unit and mark the new

point as C. Find the mid point of AC and mark

that point as 0. Draw a centre O semi-circle with and radius OC. Draw a line perpendicular to

AC pas sing through B

and intersecting the semi-circle

at D. 1¼ then BD

= .J9 ../9 on To represent the number line, let us treat the line BC as the number

zero (c) line, with Bas . as 1 and so on

½ Draw an arc with centre B

and radius BD which intersect the number line at E E represents ../9 :.

1 Scheme, [CBSE Marking Sol. 2016]

·,.,Ji;s p;g A O BC E -":S-- distance 4 Mark the units from a fixed point

A on ,, given line to obtain a poin t

B such that AB = 4. units. From B, mark a d istance of 1 unit and mark the new point as C. Find the mid-point of

and mark AC that point as 0. Draw a

semi-circle with centre O and radius OC. Draw a line

perpendicular to AC passing throu gh Band intersecting the se

mi-circle a t D. Then , BD

= To represent on the

number line, let us treat th e line BC as th e numb

er lin e, with B as zero,

C as 1, and so on.

1 Draw an arc with centr e

B an d radiu s BD, which intersect s th e number line at

E. 1 ents :. E repre s

1 18] Q. 6 Repre sent ,/9.

on the number line. [Delhi Board Sol. 2013 Board Term I, 20 11, Set-12; 2010 , Set Bl 2012 , Set-50] ':-: i ....... ····•., .... ./9 _l./9._ A 0; BCE

1 +-- 9 .3---+++ ) , 1 Mark the distance 9 unit s from a fixed point A on a given line to obtain a point B such that AB = 9 units from B, mark a distance of 1 unit C. Find and mark the new point as

the mid -point of AC and mark that point as

  1. Draw a semi- circle with centre O and

Draw a line radiu s OC. perpendicular to AC

passin g through B and intersecting the semi-circle at D.

1 Then,BD= J9.

1 ent J93 on To repre s the numbe r line us tre at the line BC as the numb

er line, with B as zero, C and so on. as 1, Draw an arc with centre B and radius BD, which intersect s the number line at

E. 1 ,/9 :. E represents [CBSE Marking Scheme, 2013] ~] ~Examine whether

is rational or irrati ona

l. [Board Term I, 2016, Set

QGL21FS]

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Mathematics Class 9 Real Numbers Topic 1 and 2

Course: Engineering Mathematics I (2K6EN101)

198 Documents
Students shared 198 documents in this course

University: Kannur University

Was this document helpful?
2 ]
a
TOPIC-1
Rational
Numbers
Quick
Review
..
can
1,e
be~
1f
JI
, . d
ational
num , d q
-t
0,
,.
Rt1bon.1I
Sumber
:
A
number r
,s
c
alle
a r
rime integers
an
wntl..-71
tn
the
form
p.
q,
where
1'
and q
ar
e
c
o-p
denoted
by
(l
.
For C\ amplc 1
4
2'
4'
5'
2 . I
number
s.
clc.
are
a
ll
ra
tiona
3
{
1?.
q
O
and
p, q
E
,J
Symbolrcallv,
Q
""
q'
roPlC - 1
,.
.
r
na
;
rr
.b.
r.
~,.
~.)
roPIC -
5 _
liz
.,r r
r'
.,
;,.-
P.
atio
na
ciu:J,.
V•
,:-::
imal
expansion
of
real
,.
Decimal Expansion
of
Real Numbers : The dee
r
numbe r
u--ed
to
re
pr
e, ent
a
number on the number
me
.
emunating
recurri
ng,
than
th
e real;_
. . . . emunating
or
non-t
It
the d
ea
mal
ex
pansion of a real numbens either
1
1,
ca
ll~
>d
a
rational number.
Cases in Rational Number:
be p
(q
-t
0)
can
be
ex
pre
ssed
as a dea..,,
Case 1 : 'When Remainder becomes Zero -
Every
rational
num
r
q'
d .
al
is
called
a
terminati
ng
decima
l.
di\
i ding
p
by
q,
when the remainder becomes zero, then the ecun
e.g.
:
(i)
.!.
=
0.5
2
· al so 1 is a
terminating
d
eamal.
On
dividing
1
by
2,
we get
value
0.5
i.e.
, remamder equ lo zero, 2
(ii)
52
=
0.
52
100
52 . .
tJ
d . I
On
dividing
52
by
100,
we get
value
0.52
i.e
., remainder equal
to
zero, so -
JS
a
term
ma
ng
ea
ma .
100
Case 2 : When remainder never becomes zero - A rational
number
expressed in
the
form
of
p.
q
or
d1\
1510!1
by
q,
when remainder never becomes zero
and
set
of
digits repeats periodicall y th
an
t
he
deamal
is
cafl~d
terminating recurring
or
repeating decimal.
It
is denoted by the bar
over
it.
. 1 -
e.g. :
(1)
-
=
0.333
....
=
0.
3
3
On dividing
1
by
3,
we get 3 again and again
i.e.,
remainder
never
becomes zero,
50
113
is
a
repeating
decim
(ii)
=
0.272727
..
..
=
0.27
11
On dividing 3 by
11,
we get
27 again and again
i.e.,
remainder neve
be
r comes zero.
So
, J
1
11
is a repeatin g de
,.
Every integer is a rational number.
, There are infinitely many rational numbers between
any
two · . .
gnen
rational
numbers
.
,
If
x
and
y
are
any
two rational numbers, then :
(i)
x +
y
is a
rational number
(ii) x -
y
is a
rational number
(ili)x
x
y
is
a
rational number
(iv)
x +
y
is
a
rational number,
(y
#
OJ.