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TEST 1 ITT300 UITM

Course

Data Communication Networking (ITT300)

184 Documents
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Universiti Teknologi MARA

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UNIVERSITI TEKNOLOGI MARAONLINE TEST

COURSE : INTRODUCTION DATA COMMUNICATION AND NETWORKING

COURSE CODE : ITT

DATE : DECEMBER 2020

TIME : 2½ HOURS

INSTRUCTIONS TO CANDIDATES 1. This question paper consists of PART A (Objective – ONLINE UFUTURE)PART B (6 QUESTIONS) PART C (1 QUESTION) 2. Answer PARTB and PART C questions in this question paper. 3. Please be honest. Do not share OR copy and paste answer with your friends

Name/UiTM No.:

Program/Group:

DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO DO SO

PART B (30 Marks) QUESTION 1

a) Identify issues in the given Figure 1 during digital-to-digital transmission -lack of synchronization

(1 Marks) b) Explain cause and to solve issue on the Figure 1 during digital-to-digital transmission. -the problem comes from receiver clock and cycles is not balanced for bits,

QUESTION 3

A beam of light moves from one medium to another medangle is 50°. Draw diagram to represent the bending of the light ray in each case. Identifyium with less density. The critical whether refraction or reflection for each of the following incident angles? a. 40° b. 60°

(5 Marks) QUESTION 4 a) Why Shielded Twisted Pair (STP) cable is better than- STP cables are good for high-speed, compare to UTP, networks. Unshielded Twisted Pair Cable? STP provides better protection against interference and crosstalk benefit from it’s shielding.

(2 Marks) b) Complete the following given Table 2 below.

X = RJ

Y = Coxial cable

(4 Marks) QUESTION 6 a) Why the statistical TDM is more outstanding over synchr- onous TDM? synchronous TDM waste the slots if the source does not have any data,dynamically on demand. then, if slot does not have any data, slot can be us statistical TDM allocates slotse bu another data.

(1 Mark) b) Given the diagram 1, provide the output of data resynchronous TDM demultiplexer. present by each channel after using

Channel 1 =HI______________

Channel 2 = MY Channel 3 = NAME Channel 4 = JENA

(4 Marks) PART C (10 Marks) There are ten signal sources which are multiplexed using Multiplexing: synchronous Time Division

  • • First two source channel with six pages to sendThree channels with four pages to send
  • Each page has an average of 20 lines with 50 charactersAnother five sources with two pages to send in each line. Assume that there is byte interleaving and that each frame requires 4 bits for synchronization. i. What is the bit rate for each of the source channel ( number of lines x number of characters x 8 bits )? hint: bit rate = number of pages x a. Channel with 6 pages? 62050*8=48K bits per second
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TEST 1 ITT300 UITM

Course: Data Communication Networking (ITT300)

184 Documents
Students shared 184 documents in this course

University: Universiti Teknologi MARA

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CONFIDENTIAL CS/TEST/DEC 2020/ITT300
UNIVERSITI TEKNOLOGI MARA
ONLINE TEST
COURSE : INTRODUCTION DATA COMMUNICATION AND
NETWORKING
COURSE CODE : ITT300
DATE : DECEMBER 2020
TIME : 2½ HOURS
INSTRUCTIONS TO CANDIDATES
1. This question paper consists of PART A (Objective – ONLINE UFUTURE)
PART B (6 QUESTIONS)
PART C (1 QUESTION)
2. Answer PARTB and PART C questions in this question paper.
3. Please be honest. Do not share OR copy and paste answer with your friends
Name/UiTM No.:
Program/Group:
DO NOT TURN THIS PAGE UNTIL YOU ARE TOLD TO DO SO
© Hak Cipta Universiti Teknologi MARA CONFIDENTIAL

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