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PHYS101L-E102 - PHYS101 Laboratory- Experiment 102 Friction lab report
Physics for Engineering-Laboratory (PHYS101L)
Mapúa University
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MAPÚA UNIVERSITY
Department of Physics
Experiment No. 2
Title: Friction
PHYS101L/ A4 Group No. 2
Group Leader: Jimenez, Froi Christian C.
Date of Submitted: 09/02/
Name Contribution of Group Member in the Experiment Report
Members Rating (10)
Jimenez, Froi
Christan C.
Group data, Conclusion 10
Kim, Lloyd Anthony Analysis 10
Lachica, Emilio
Miguel D.
Analysis 10
Llevado, Janus Guide questions 10
Macabasco, Jaytee M. Computation and Group
data
10
Mansilungan, Ma.
Theressa Camille M.
Computation 10
CRITERIA FOR GRADING A) Data Sheet / Graphs, Figures and Tables 20% B) Complete Computations 10% C) Analysis and Conclusion 50% D) Answers to Questions 10% E) Presentation/Completeness 10% TOTAL
100 %
A) GROUP DATA:
PART A. Determination of the Coefficient of Friction
TABLE 1a. (large side of the block)
(total weight of the block) Wb
(total weight of the pan) Wp
Coefficient of friction μ
124 g 30 g 0.
224 g 55 g 0.
324 g 75 g 0.
Average Coefficient of Friction μ = 0.
Figure 1: From data gathered in Table 1a
1. Compute the slope of the graph: Slope = 0. 2. Compare the slope of the graph and the average value of μ in Part A:
The computation for the slope = ÿ𝕖ĀÿÿĂÿ= Āÿý Āÿý 𝕊ā ÷ ÿÿÿĀā 𝕊ā𝕊Ā – Ā𝕖ÿ𝕖þĂþ 𝕊Ā = 324 2 124 ÷ 30 = 2. 612 = 0.
The average value of μ in Part A = 𝔴ćă. 𝔇 =𝗴𝔇 = ĀĂþþÿā𝕖Āÿ ÿ = ÿĂþĀÿÿ ĀĀ āĀÿĀĀ𝕖ā𝕖ÿÿā ĀĀ āÿ𝕖ÿýĀĀĀ Āÿ𝕖āā𝕖Āÿ 0. 2415+0. 2453+0. 2313 3 =
- 7181 3 = 0 = 0.
3. Interpretation: The data gathered from Table 1a and Table 1b are computed to yield the slope of 0 while the average value of μ in part A yields 0. However, the comparative values of the two make the slope of the graph higher. Table A and figure 1 data show that the increase of the total weight of the block and the total weight of the pan does not affect the coefficient of friction on the large side of the block. The same goes for the narrow side of the block, as the data from table A/figure 1 and table B/figure 2 is the same, the computation for the coefficient of friction from the given data yields the same result.
PART B. Determination of the Angle of Repose
TABLE 2.
Vertical height
h
Horizontal distance b
tan θ θ
23 cm 98 cm 0 13°
B) COMPLETE COMPUTATIONS:
Part A Given: ý = āĀÿĄąÿÿą ÿ = 0 i. Large side of the block Trial 1 𝔇 =Āÿ eq (1) 𝗴𝔹 = 0 𝗴𝔹ý= 0 Ą 2 = 0 Ą = eq (2) 𝗴𝔹þ= 0 2 þā= 0 = þā eq (3) eq (2) = eq (3) Ą = þā ÿ 2 þĀ= 0 ÿ = þĀ 𝔇 =Ąÿ=þþāĀ 𝔇 =124 ą30 ą 𝔇 = 0. 2415 = 0. 24 Trial 2 𝔇 =Āÿ eq (1) 𝗴𝔹 = 0 𝗴𝔹ý= 0 Ą 2 = 0 Ą = eq (2) 𝗴𝔹þ= 0 2 þā= 0 = þā eq (3) eq (2) = eq (3) Ą = þā ÿ 2 þĀ= 0 ÿ = þĀ 𝔇 =Ąÿ=þþāĀ 𝔇 =244 ą55 ą
Trial 3 𝔇 =Ąÿ=þþāĀ
𝔇 =324 ą75 ą 𝔇 = 0. 2313 = 0. 23
Average coefficient 𝔴ćă. 𝔇 =𝗴𝔇ÿ ÿ = ÿĆþĀăă ĀĄ ąăÿÿýĄ = 3 𝗴𝔇 = 0. 2415+ 0. 2453+ 0. 2313 = 0. 7181 𝔴ćă.𝔇 =0. 7181 3 = 0. 2394 𝔴ćă.𝔇 = 0. 2394 = 0. 24
Part B Free body diagram:
x
y
n
Wb F
θ
23.
98.
x
Wb
𝗴𝕭 = 𝗎
𝗴𝕭ý= 𝗎 𝖇 2 𝕾ÿ𝖔𝖊ÿ𝔽 = 𝗎 𝖇 = 𝕾ÿ𝖔𝖊ÿ𝔽 eq (1) 𝗴𝕭þ= 𝗎 ÿ 2 𝕾ÿĀĀ𝖔𝔽 = 𝗎 ÿ = 𝕾ÿĀĀ𝖔𝔽 eq (2) 𝔇 =Ąÿ=ăĂ (1)ăĂ (2) 𝔇 =𝕾𝕾ÿÿ𝖔𝖊ÿ𝔽ĀĀ𝖔𝔽=ĀĀ𝖔𝔽𝖔𝖊ÿ𝔽= ąÿÿ𝔃 ąÿÿ𝔃 =ÿĂĀÿāăÿąĀāāĀĄÿąă=/Ā / Ā=
23 āþ 98 āþ= 0. 2383 𝔇 = 0. 2383 𝔇 = ąÿÿ𝔃 ąÿÿ𝔃 = 0. 2383 𝔃 = 13.
C) ANALYSIS:
In this experiment, we are still going to talk about the laws of motion. However, there will be a new concept that we will be using throughout the experiment. This concept is friction. A force that is resisting the sliding and rolling of an object is called friction. Friction has two conditions: static and kinetic friction. The difference is that static friction starts from rest to motion, while kinetic friction starts from movement up until the object comes at rest. The two concepts, such as coefficient of friction and angle of repose, are introduced in this experiment. These concepts are vital and critical to the investigation.
From the data that we computed and gathered, tables 1a and 1b show similarities. Their friction coefficient varies despite the block's weight, and the mass of the pan is increasing. It is not guaranteed whether an object with a greater abundance and weight can produce a more significant coefficient of friction. We can see this result from each of the tables. Why is that? The main reason behind it is that friction can only be directly proportional to the mass. If the object is at rest or in motion in an inclined plane from this scenario, the normal force of the thing will vary its result. At
D) GUIDE QUESTIONS:
1. Does the area of contact affect the coefficient of friction? Defend your answer. Yes, since friction is simply two surfaces in contact with each other, the larger the contact area, the more atoms are exposed to the other surface, resulting in increased friction.
2. Why is it necessary to observe uniform motion of the block in each procedure of the experiment? Uniform motion is important because kinetic friction is constant when a body moves at a constant speed, meaning that the coefficient of friction of a surface is constant along its length.
PHYS101L-E102 - PHYS101 Laboratory- Experiment 102 Friction lab report
Course: Physics for Engineering-Laboratory (PHYS101L)
University: Mapúa University
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